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a = 49, b = 59

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Carcass
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a = 49, b = 59 [#permalink] New post   19 Apr 2019, 11:19
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a = 49, b = 59

Quantity A
Quantity B
\(\frac{a^2-b^2}{a-b}\)
\(\frac{a^2-b^2}{a+b}\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
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GreenlightTestPrep
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Re: a = 49, b = 59 [#permalink] New post   21 Apr 2019, 06:30
Carcass wrote:
a = 49, b = 59

Quantity A
Quantity B
\(\frac{a^2-b^2}{a-b}\)
\(\frac{a^2-b^2}{a+b}\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.


Since a = 49 and b = 59, we know that a-b ≠ 0, and we know that a+b ≠ 0

So, we have:
QUANTITY A:\(\frac{a^2-b^2}{a-b}=\frac{(a+b)(a-b)}{a-b}=a+b=49+59=108\)

QUANTITY B: \(\frac{a^2-b^2}{a+b}=\frac{(a+b)(a-b)}{a+b}=a-b=49-59=-10\)

Answer: A

Cheers,
Brent
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Re: a = 49, b = 59 [#permalink]
21 Apr 2019, 06:30
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