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A 5-liter jug contains 4 liters of a saltwater solution that
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04 Sep 2020, 12:36
04 Sep 2020, 12:36
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Question Stats:
64% (01:48) correct
35% (02:11) wrong based on 42 sessions
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A 5-liter jug contains 4 liters of a saltwater solution that is 15 percent salt. If 1.5 liters of the solution spills out of the jug, and the jug is then filled to capacity with water, approximately what percent of the resulting solution in the jug is salt?
(A) \(7\frac{1}{2}\)%
(B) \(9\frac{3}{8}\)%
(C) \(10\frac{1}{2}\)%
(D) \(12\)%
(E) \(15\)%
(A) \(7\frac{1}{2}\)%
(B) \(9\frac{3}{8}\)%
(C) \(10\frac{1}{2}\)%
(D) \(12\)%
(E) \(15\)%
Re: A 5-liter jug contains 4 liters of a saltwater solution that
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04 Sep 2020, 12:38
04 Sep 2020, 12:38
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Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
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Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
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Re: A 5-liter jug contains 4 liters of a saltwater solution that
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04 Sep 2020, 20:08
04 Sep 2020, 20:08
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Carcass wrote:
A 5-liter jug contains 4 liters of a saltwater solution that is 15 percent salt. If 1.5 liters of the solution spills out of the jug, and the jug is then filled to capacity with water, approximately what percent of the resulting solution in the jug is salt?
(A) \(7\frac{1}{2}\)%
(B) \(9\frac{3}{8}\)%
(C) \(10\frac{1}{2}\)%
(D) \(12\)%
(E) \(15\)%
(A) \(7\frac{1}{2}\)%
(B) \(9\frac{3}{8}\)%
(C) \(10\frac{1}{2}\)%
(D) \(12\)%
(E) \(15\)%
So we have 4 Liters of salt water solution which is made up of 15% salt.
Then 1.5 liters spilled out. That means there is 2.5 liters left, which is still made up of 15% salt.
\(2.5 * 0.15 = 2.5(0.10 + 0.05) = 0.25 + 0.125 = 0.375\) of salt in the solution.
Then the jug is filled to capacity with only water, so 2.5 liters of water are added.
We're being asked: what percent of the final solution is salt?
We know the capacity is 5 liters, and there is 0.375 liters of salt in the water so:
\(\frac{0.375}{5} = \frac{(0.375 * 2) }{ 10} = \frac{ 0.75 }{ 10} = 0.075\)
They want this as a percentage:
\(0.075 * 100 = 7.5\)% \(= 7 \frac{1}{2}\)%
The answer is A
