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A, B and C do a business together. After they share profits, A got 20%
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08 Jul 2024, 22:53
08 Jul 2024, 22:53
Expert Reply
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Question Stats:
50% (01:10) correct
50% (01:44) wrong based on 2 sessions
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A, B and C do a business together. After they share profits, A got 20% more than B, but 40% less than C. The percentage by which B got less than C is
Show: ::
50
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Shorter GRE - Preparing for the Quantitative Reasoning Measure
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Re: A, B and C do a business together. After they share profits, A got 20%
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11 Jul 2024, 10:18
11 Jul 2024, 10:18
Carcass
I'm getting asnwer as 100%. Please let me know where am I making mistake?
A = 120B / 100 = 60C/100
B= 100A/120
C= 100A/60
The percentage by which B got less than C
= C-B/B *100
= [100A/60 - 100A/120] / [100A/120] *100
= [100A/120] / [100A/120] *100
= 1 *100
= 100%
I'm getting asnwer as 100%. Please let me know where am I making mistake?
A = 120B / 100 = 60C/100
B= 100A/120
C= 100A/60
The percentage by which B got less than C
= C-B/B *100
= [100A/60 - 100A/120] / [100A/120] *100
= [100A/120] / [100A/120] *100
= 1 *100
= 100%
A, B and C do a business together. After they share profits, A got 20%
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11 Jul 2024, 10:38
11 Jul 2024, 10:38
Expert Reply
First thing first see my chapter about % where I explained the concepts extensively.
https://gre.myprepclub.com/forum/gre-ma ... tml#p81625
They key here is to start from C which I do not know and therefore we can label as 100
C=100
Then
A got 20% more than B,
\(A=1.2B\)
but 40% less than C.
\(A=0.6C\)
Substitute to find B
\(0.6C=1.2B\)
\(C=100\)
\(0.6*100=1.2B\)
\(\frac{60}{1.2}=B\)
\(B = 50\)
I hope this helps
https://gre.myprepclub.com/forum/gre-ma ... tml#p81625
They key here is to start from C which I do not know and therefore we can label as 100
C=100
Then
A got 20% more than B,
\(A=1.2B\)
but 40% less than C.
\(A=0.6C\)
Substitute to find B
\(0.6C=1.2B\)
\(C=100\)
\(0.6*100=1.2B\)
\(\frac{60}{1.2}=B\)
\(B = 50\)
I hope this helps
