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A botanist designates each plant with a one-, two- or three-letter cod
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30 Nov 2023, 23:52
30 Nov 2023, 23:52
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Question Stats:
80% (01:05) correct
20% (02:39) wrong based on 5 sessions
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A botanist designates each plant with a one-, two- or three-letter codes, where each letter is one among the 26 letters of the alphabets. If the letters may be repeated and if the same letters used in a different order convey a different code, how many different plants can the botanist uniquely designate with these codes?
(A) 2,951
(B) 9,125
(C) 16,600
(D) 17,576
(E) 18,278
(A) 2,951
(B) 9,125
(C) 16,600
(D) 17,576
(E) 18,278
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Re: A botanist designates each plant with a one-, two- or three-letter cod
[#permalink]
03 Dec 2023, 00:41
03 Dec 2023, 00:41
2
The answer is E.
# of 1-blank codes = 26
# of 2-blank codes = 26*26 = 676
# of 3-blank codes = 26*26*26 = 17,576
--> Total = 26 + 676 + 17576 = 18,278
# of 1-blank codes = 26
# of 2-blank codes = 26*26 = 676
# of 3-blank codes = 26*26*26 = 17,576
--> Total = 26 + 676 + 17576 = 18,278
gmatclubot
Re: A botanist designates each plant with a one-, two- or three-letter cod [#permalink]
03 Dec 2023, 00:41
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