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A byciclist travels up the hill at 10 miles per hour
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29 Jun 2020, 05:33
29 Jun 2020, 05:33
Expert Reply
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Question Stats:
90% (01:02) correct
9% (00:40) wrong based on 33 sessions
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A bicyclist travels up the hill at 10 miles per hour and returns down the same hill at 30 miles per hour. What is his/her average speed, in miles per hour, for the entire journey up and down the hill ?
A. 15
B. 17
C. 20
D. 22
E. 25
A. 15
B. 17
C. 20
D. 22
E. 25
Re: A byciclist travels up the hill at 10 miles per hour
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29 Jun 2020, 05:33
29 Jun 2020, 05:33
Expert Reply
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
Re: A byciclist travels up the hill at 10 miles per hour
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29 Jun 2020, 10:06
29 Jun 2020, 10:06
2
Let the distance one way = D
Average Speed = \frac{Total Distance}{Total Time}
Time uphill = \(\frac{D}{10}\)
Time downhill = \(\frac{D}{30}\)
Total time = \(\frac{D}{10} + \frac{D}{30} = \frac{30D+10D}{30 \times 10} = \frac{40D}{300}\)
Total Distance \(= D + D = 2D\)
Average Speed = \(2D / \frac{40D}{300} = \frac{2D \times 300}{40} = 15\)
OA, A
Average Speed = \frac{Total Distance}{Total Time}
Time uphill = \(\frac{D}{10}\)
Time downhill = \(\frac{D}{30}\)
Total time = \(\frac{D}{10} + \frac{D}{30} = \frac{30D+10D}{30 \times 10} = \frac{40D}{300}\)
Total Distance \(= D + D = 2D\)
Average Speed = \(2D / \frac{40D}{300} = \frac{2D \times 300}{40} = 15\)
OA, A
Carcass wrote:
A bicyclist travels up the hill at 10 miles per hour and returns down the same hill at 30 miles per hour. What is his/her average speed, in miles per hour, for the entire journey up and down the hill ?
A. 15
B. 17
C. 20
D. 22
E. 25
A. 15
B. 17
C. 20
D. 22
E. 25
