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A certain fruit stand sold apples for $0.70 each and bananas
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16 Jun 2020, 03:34
16 Jun 2020, 03:34
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Question Stats:
75% (02:21) correct
24% (02:41) wrong based on 37 sessions
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A certain fruit stand sold apples for $0.70 each and bananas for $0.50 each. If a customer purchased both apples and bananas from the stand for a total of $6.30, what total number of apples and bananas did the customer purchase?
(A) 10
(B) 11
(C) 12
(D) 13
(E) 14
(A) 10
(B) 11
(C) 12
(D) 13
(E) 14
Re: A certain fruit stand sold apples for $0.70 each and bananas
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16 Jun 2020, 03:34
16 Jun 2020, 03:34
Expert Reply
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
Re: A certain fruit stand sold apples for $0.70 each and bananas
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16 Jun 2020, 18:07
16 Jun 2020, 18:07
1
First remove decimal
equation will be:
7A + 5B = 63
5B=63-7A
B=63-7A/5
Now we have to make 63-7A as multiple of 5 only then the term will be divisible by 5. We want fruits in integer value
if A = 2
B=63-7*2=49 it is not divisible by 5
if A=4
B=63-7*4=35 and it is divisible by 5
so A=4
now solve for B
7A + 5B = 63
7*4 +5B = 63
63-28 = 35/5 = 7
B=7
A+B=4+7=11 option B
This is how I solved but would appreciate if other method is posted. Thanks
equation will be:
7A + 5B = 63
5B=63-7A
B=63-7A/5
Now we have to make 63-7A as multiple of 5 only then the term will be divisible by 5. We want fruits in integer value
if A = 2
B=63-7*2=49 it is not divisible by 5
if A=4
B=63-7*4=35 and it is divisible by 5
so A=4
now solve for B
7A + 5B = 63
7*4 +5B = 63
63-28 = 35/5 = 7
B=7
A+B=4+7=11 option B
This is how I solved but would appreciate if other method is posted. Thanks
