GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
A certain kickball team named "The good guys" won 1/3 of their first 2
[#permalink]
19 Dec 2021, 13:05
19 Dec 2021, 13:05
2
Bookmarks
00:00
Question Stats:
50% (02:45) correct
50% (01:37) wrong based on 6 sessions
Hide Show timer Statistics
A certain kickball team named "The good guys" won 1/3 of their first 24 games. If the teams lose no more than 1/9 of their remaining games, what is the least number of games they must play to ensure they win more than they loose?
a) 9
b) 10
c) 11
d) 12
e) 13
May someone tell me where is my mistake?
I tried solving backward by starting with a
\((1/9)* 9 + 16 = 17 \)
and the winning will be \((8/9) * 9 + 8 = 16 \) option a wrong
no for the rest, all of the options will give us the first option 1.something .. I round it to 2.
Until I reach 13, where the winning games is more than the lost games.
a) 9
b) 10
c) 11
d) 12
e) 13
May someone tell me where is my mistake?
I tried solving backward by starting with a
\((1/9)* 9 + 16 = 17 \)
and the winning will be \((8/9) * 9 + 8 = 16 \) option a wrong
no for the rest, all of the options will give us the first option 1.something .. I round it to 2.
Until I reach 13, where the winning games is more than the lost games.
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
Re: A certain kickball team named "The good guys" won 1/3 of their first 2
[#permalink]
04 Mar 2022, 00:58
04 Mar 2022, 00:58
1
Asmakan wrote:
A certain kickball team named "The good guys" won 1/3 of their first 24 games. If the teams lose no more than 1/9 of their remaining games, what is the least number of games they must play to ensure they win more than they loose?
a) 9
b) 10
c) 11
d) 12
e) 13
May someone tell me where is my mistake?
I tried solving backward by starting with a
\((1/9)* 9 + 16 = 17 \)
and the winning will be \((8/9) * 9 + 8 = 16 \) option a wrong
no for the rest, all of the options will give us the first option 1.something .. I round it to 2.
Until I reach 13, where the winning games is more than the lost games.
a) 9
b) 10
c) 11
d) 12
e) 13
May someone tell me where is my mistake?
I tried solving backward by starting with a
\((1/9)* 9 + 16 = 17 \)
and the winning will be \((8/9) * 9 + 8 = 16 \) option a wrong
no for the rest, all of the options will give us the first option 1.something .. I round it to 2.
Until I reach 13, where the winning games is more than the lost games.
Games Won = \(\frac{1}{3}(24) = 8\)
Games Lost = \(24 - 8 = 16\)
Let, the total number of remaning games be \(x\)
Games Lost of the remaining = \(\frac{x}{9}\), and
Games Won of the remaining = \(x - \frac{x}{9} = \frac{8x}{9}\)
As per the question;
Total games Won ≥ Total games Lost
\(8 + \frac{8x}{9} ≥ 16 + \frac{x}{9}\)
\(\frac{8x}{9} - \frac{x}{9} ≥ 8\)
\(7x ≥ 72\)
i.e. \(x ≥ 10.28\)
Hence, option C
gmatclubot
Re: A certain kickball team named "The good guys" won 1/3 of their first 2 [#permalink]
04 Mar 2022, 00:58
Moderators:
