GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
A certain office building houses five departments of the same company
[#permalink]
01 Oct 2021, 09:27
01 Oct 2021, 09:27
Expert Reply
00:00
Question Stats:
76% (01:59) correct
23% (01:49) wrong based on 21 sessions
Hide Show timer Statistics
A certain office building houses five departments of the same company and exactly 75 employees. If the numbers of employees working in the departments are consecutive odd numbers, what is the probability that a given employee works in one of the two largest departments?
(A) 48%
(B) 45%
(C) 44%
(D) 40%
(E) 32%
(A) 48%
(B) 45%
(C) 44%
(D) 40%
(E) 32%
A certain office building houses five departments of the same company
[#permalink]
01 Oct 2021, 19:29
01 Oct 2021, 19:29
1
Total employee \(= 75\) in five department
Five Consecutive ODD integers: \(2x - 3, 2x - 1, 2x + 1, 2x + 3, 2x + 5\)
Sum \(= 75 = 10x + 5\)
\(x = 7\)
Numbers \(= 11 , 13 , 15 , 17 , 19\)
Probability of a given employee works in one of the two largest departments \(= \frac{ 19 + 17 }{ 75} = \frac{36}{75} = \) \(= 48\)%
Answer A
Five Consecutive ODD integers: \(2x - 3, 2x - 1, 2x + 1, 2x + 3, 2x + 5\)
Sum \(= 75 = 10x + 5\)
\(x = 7\)
Numbers \(= 11 , 13 , 15 , 17 , 19\)
Probability of a given employee works in one of the two largest departments \(= \frac{ 19 + 17 }{ 75} = \frac{36}{75} = \) \(= 48\)%
Answer A
A certain office building houses five departments of the same company
[#permalink]
01 Oct 2021, 19:35
01 Oct 2021, 19:35
1
I think your answer above is incorrect. it asks for 5 consecutive odd integers. So it would be.
Total employee =75=75 in five department
Five Consecutive odd integers: x,x+2,x+4,x,x+6,x+8 = 75
Solve for x
x=11
Numbers =11,13,15,17,19
Probability of a given employee works in one of the two largest departments =(17+19)/75 = 48% or A
Total employee =75=75 in five department
Five Consecutive odd integers: x,x+2,x+4,x,x+6,x+8 = 75
Solve for x
x=11
Numbers =11,13,15,17,19
Probability of a given employee works in one of the two largest departments =(17+19)/75 = 48% or A
