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A coin is tossed 14 times. Heads occurs 8 times and tails 6 times. The

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A coin is tossed 14 times. Heads occurs 8 times and tails 6 times. The [#permalink] New post   01 Sep 2022, 10:12
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A coin is tossed 14 times.
Heads occurs 8 times and tails 6 times.
The second and thirteenth tosses are heads.

Quantity A
Quantity B
maximum number of heads that can occur in a row
8



A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given

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B
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B
dilotor
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Re: A coin is tossed 14 times. Heads occurs 8 times and tails 6 times. The [#permalink] New post   01 Sep 2022, 13:13
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Tosses: 1 2 3 4 5 6 7 8 9 10 11 12 13 14
2nd and 13th are Head H H
Head occurs 8 times so you have 6 left H H H H H H H = 7 consecutive heads
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Re: A coin is tossed 14 times. Heads occurs 8 times and tails 6 times. The [#permalink] New post   02 Sep 2022, 07:51
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given that the 2nd and 13th toss gives head , at the maximum only 7 consecutive heads are possible .

Thus , B is the answer.
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Re: A coin is tossed 14 times. Heads occurs 8 times and tails 6 times. The [#permalink] New post   23 Oct 2022, 09:24
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Given that A coin is tossed 14 times. Heads occurs 8 times and tails 6 times. The second and thirteenth tosses are heads.

Quantity A: Maximum number of heads that can occur in a row

We know that \(2^{nd}\) and \(13^{th}\) toss are heads and we have only 8 heads.
SO, 7 of them can occur together, which can include either the \(2^{nd}\) or the \(13^{th}\) toss.

Clearly, Quantity B(8) > Quantity A(7)

So, Answer will be B
Hope it helps!

Watch the following video to learn How to Solve Probability with Coin Toss Problems

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Re: A coin is tossed 14 times. Heads occurs 8 times and tails 6 times. The [#permalink]
23 Oct 2022, 09:24
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