GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
A man covered 1 3 of the distance to his destination at 20 miles per h
[#permalink]
26 Jan 2024, 00:35
26 Jan 2024, 00:35
Expert Reply
00:00
Question Stats:
81% (03:12) correct
18% (02:06) wrong based on 11 sessions
Hide Show timer Statistics
A man covered 1/3 of the distance to his destination at 20 miles per hour, 1/2 of the remaining distance at 12 miles per hour and remaining distance at 40 miles per hour. Which of the following statements is true regarding the entire journey?
Indicate all possible statements.
(A) Time taken to travel the part of the distance at 40 miles per hour was 1/2 of the time taken to cover the part of the distance at 20 miles per hour.
(B) Total time taken to complete the entire journey was 18 hours.
(C) Average speed for the entire journey is 20 miles per hour.
Indicate all possible statements.
(A) Time taken to travel the part of the distance at 40 miles per hour was 1/2 of the time taken to cover the part of the distance at 20 miles per hour.
(B) Total time taken to complete the entire journey was 18 hours.
(C) Average speed for the entire journey is 20 miles per hour.
Part of the project: GRE-Problem Solving Practice Questions Special Edition {PS,MAC, & NE} - Gain 20 Kudos & Get FREE Access to GRE Prep Club TESTS
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
Manager
Joined: 11 Nov 2023
Posts: 207
Given Kudos: 76
WE:Business Development (Advertising and PR)
A man covered 1 3 of the distance to his destination at 20 miles per h
[#permalink]
26 Jan 2024, 16:29
26 Jan 2024, 16:29
1
There's no mention of actual distance, only of actual rates. That means we can't determine actual total time, which rules out (B).
Let's say actual total distance = 360.
Distance traveled at 20mph \(= \frac{1}{3} * 360 = 120\)
1/2 the remaining distance \(\frac{1}{2} * (360 - 120) = 120\)
The remaining distance \(= 360 - (120+120) = 120\)
Let a = Time taken to travel the part of the distance at 20 mph, b = Time taken to travel the part of the distance at 12 mph, and c = Time taken to travel the part of the distance at 40 mph.
Using the distance-rate formula, t = d/r :
\(a = 120 / 20 = 6\)
\(b = 120 / 36 = \frac{10}{3}\)
\(c = 120 / 40 = 3\)
Since c = 1/2a, (A) is correct.
The average speed for the entire journey = \(\frac{360}{6 + \frac{10}{3} + 3} = 18.95\), so (C) is incorrect.
Let's say actual total distance = 360.
Distance traveled at 20mph \(= \frac{1}{3} * 360 = 120\)
1/2 the remaining distance \(\frac{1}{2} * (360 - 120) = 120\)
The remaining distance \(= 360 - (120+120) = 120\)
Let a = Time taken to travel the part of the distance at 20 mph, b = Time taken to travel the part of the distance at 12 mph, and c = Time taken to travel the part of the distance at 40 mph.
Using the distance-rate formula, t = d/r :
\(a = 120 / 20 = 6\)
\(b = 120 / 36 = \frac{10}{3}\)
\(c = 120 / 40 = 3\)
Since c = 1/2a, (A) is correct.
The average speed for the entire journey = \(\frac{360}{6 + \frac{10}{3} + 3} = 18.95\), so (C) is incorrect.
gmatclubot
A man covered 1 3 of the distance to his destination at 20 miles per h [#permalink]
26 Jan 2024, 16:29
Moderators:
