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Re: A set consists of 11 different numbers. If x is a number in the list a
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17 Jan 2024, 23:18
Let \(a\) = the average of the other 10 numbers in the list.
Since \(x\) is three times the average of the other 10 numbers in the list, \(x = 3a\).
The sum of the 11 numbers in the list is \(10a + x = 10a + 3a = 13a\).
\(\frac{x }{ 13a} = \frac{3a }{ 13a} = \frac{3}{13}\)