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An alloy A is formed by mixing gold and silver in the ratio 2 : 1. Ano
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26 Oct 2021, 09:50
26 Oct 2021, 09:50
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Question Stats:
61% (02:51) correct
38% (03:14) wrong based on 18 sessions
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Alloy A is formed by mixing gold and silver in the ratio 2 : 1 by weight. Alloy B is formed by mixing silver and platinum in the ratio 3 : 4. Alloy C is obtained by mixing alloys A and B in a certain ratio such that the ratio of gold to platinum in alloy C is 5 : 6. Which of the following correctly represents the fraction of silver in alloy C?
A. 29/51
B. 37/13
C. 17/31
D. 49/126
E. 19/35
A. 29/51
B. 37/13
C. 17/31
D. 49/126
E. 19/35
Re: An alloy A is formed by mixing gold and silver in the ratio 2 : 1. Ano
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26 Oct 2021, 13:48
26 Oct 2021, 13:48
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Is this math correct? I did the following:
First, we want Alloy C to have the ratio of gold to platinum to be 5 to 6. I multiplied by 2 (this helps down the road) to get 10 gold to 12 platinum.
In Alloy A, 10 Gold will give us 5 Silver. In Alloy B, 12 Platinum will give us 9 Silver.
In total, we have 10 Gold + 5 Silver + 9 Silver + 12 Platinum = 36 in total
5+9 = 14/36 = 7/18
7/18 is the same as 49/126
First, we want Alloy C to have the ratio of gold to platinum to be 5 to 6. I multiplied by 2 (this helps down the road) to get 10 gold to 12 platinum.
In Alloy A, 10 Gold will give us 5 Silver. In Alloy B, 12 Platinum will give us 9 Silver.
In total, we have 10 Gold + 5 Silver + 9 Silver + 12 Platinum = 36 in total
5+9 = 14/36 = 7/18
7/18 is the same as 49/126
Re: An alloy A is formed by mixing gold and silver in the ratio 2 : 1. Ano
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21 Jul 2024, 23:56
21 Jul 2024, 23:56
Explanation please?
