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An arithmetic sequence of 12 positive consecutive integers starts with
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27 Mar 2023, 08:34
27 Mar 2023, 08:34
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Question Stats:
68% (01:26) correct
31% (01:49) wrong based on 38 sessions
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An arithmetic sequence of 12 positive consecutive integers starts with x.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
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\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
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Quantity A |
Quantity B |
The sum of all even numbered terms |
The sum of all odd numbered terms |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE SEQUENCES
Re: An arithmetic sequence of 12 positive consecutive integers starts with
[#permalink]
27 Mar 2023, 18:39
27 Mar 2023, 18:39
2
If we take sequence from 1 to 12. Odd sum = 36 and even sum = 42
If we take sequence from 2 to 13. Odd sum = 48 and even sum = 42
Even sum can be greater and smaller in two different cases
Cannot be determined
If we take sequence from 2 to 13. Odd sum = 48 and even sum = 42
Even sum can be greater and smaller in two different cases
Cannot be determined
Re: An arithmetic sequence of 12 positive consecutive integers starts with
[#permalink]
10 May 2026, 06:10
10 May 2026, 06:10
1
The numbers are x, x + 1, x + 2, ..., x + 11.
One set of numbers = x, x + 2, x + 4, x + 6, x + 8, x + 10 --> Sum = 6x + 30
The other set of numbers = x + 1, x + 3, x + 5, x + 7, x + 9, x + 11 --> Sum = 6x + 36
Obviously, 6x + 36 is greater. However, we do not know which set is that of even numbers and which one is that of odd numbers. Hence, it cannot be determined.
The answer is D.
One set of numbers = x, x + 2, x + 4, x + 6, x + 8, x + 10 --> Sum = 6x + 30
The other set of numbers = x + 1, x + 3, x + 5, x + 7, x + 9, x + 11 --> Sum = 6x + 36
Obviously, 6x + 36 is greater. However, we do not know which set is that of even numbers and which one is that of odd numbers. Hence, it cannot be determined.
The answer is D.
