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An item’s price was discounted by 16%. Later, the discounted
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10 Jun 2018, 03:58
10 Jun 2018, 03:58
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Question Stats:
94% (00:34) correct
5% (00:07) wrong based on 71 sessions
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An item’s price was discounted by 16%. Later, the discounted price was increased by 16%.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The original price |
The price after the discount and increase |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Re: An item’s price was discounted by 16%. Later, the discounted
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13 Jun 2018, 16:34
13 Jun 2018, 16:34
Expert Reply
Explanation
The problem doesn’t indicate any specific values, so pick a smart number. Because this is a percent problem, call the original price $100. Quantity A equals $100.
Decreasing a value by 16% is the same as taking (100 – 16)% = 84% of the number: so (0.84)(100) = $84.
To increase the value by 16%, take 116% of the number, or multiply by 1.16: (1.16)(84) = $97.44.
Quantity A is greater.
The problem doesn’t indicate any specific values, so pick a smart number. Because this is a percent problem, call the original price $100. Quantity A equals $100.
Decreasing a value by 16% is the same as taking (100 – 16)% = 84% of the number: so (0.84)(100) = $84.
To increase the value by 16%, take 116% of the number, or multiply by 1.16: (1.16)(84) = $97.44.
Quantity A is greater.
Re: An item’s price was discounted by 16%. Later, the discounted
[#permalink]
13 Jun 2018, 17:27
13 Jun 2018, 17:27
Assume the original price = P
Quantity A = P
Quantity B = P*(1-16%)*(1+16%) = P(1-0.16^2) < P = A
--> A > B
Keys: A
Quantity A = P
Quantity B = P*(1-16%)*(1+16%) = P(1-0.16^2) < P = A
--> A > B
Keys: A
