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Daniel is playing a dice game in which
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08 Jun 2019, 05:09
08 Jun 2019, 05:09
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22% (02:39) correct
77% (02:12) wrong based on 127 sessions
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Daniel is playing a dice game in which a dice is rolled 5 times. If a number turns up exactly 3 times then the game is won. Daniel has thrown the dice two times and got number 4 both times. What is the probability that Daniel will win the game ?
Note: the dice is an unbiased die with numbers 1 to 6
a) 1/216
b) 75/216
c) 80/216
d) 90/216
e) 100/216
Note: the dice is an unbiased die with numbers 1 to 6
a) 1/216
b) 75/216
c) 80/216
d) 90/216
e) 100/216
Re: Daniel is playing a dice game in which
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18 Aug 2020, 15:31
18 Aug 2020, 15:31
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The game is won when 1 number show up Exactly 3 times
We are given first two throw result in 4 so we need one more 4 to win , this can be done in 1*1*5/6*5/6*1/6*3
where 5/6 is probability of not getting 4 and they can be arranged in 3 ways.
Now we can also win the game if we get rest of numbers 3 times i.e 1,2,3,5,6
so probability will be =5*1/6*1/6*1/6
The probability of winning =5/216+75/216=80/216
Regards
We are given first two throw result in 4 so we need one more 4 to win , this can be done in 1*1*5/6*5/6*1/6*3
where 5/6 is probability of not getting 4 and they can be arranged in 3 ways.
Now we can also win the game if we get rest of numbers 3 times i.e 1,2,3,5,6
so probability will be =5*1/6*1/6*1/6
The probability of winning =5/216+75/216=80/216
Regards
General Discussion
Re: Daniel is playing a dice game in which
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18 Aug 2020, 15:31
18 Aug 2020, 15:31
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Expert Reply
Bump for further discussion
