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The probability of drawing a regular polygon
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25 May 2020, 10:40
25 May 2020, 10:40
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Question Stats:
87% (00:50) correct
12% (01:50) wrong based on 16 sessions
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A regular polygon will be drawn with a number of sides randomly chosen from the whole number 3 through 10 . what is the probability that the internal angles will be greater than 110 ?
A) 1/8
B) 1/4
C) 3/8
D) 1/2
E) 5/8
A) 1/8
B) 1/4
C) 3/8
D) 1/2
E) 5/8
Re: The probability of drawing a regular polygon
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25 May 2020, 15:08
25 May 2020, 15:08
2
each internal angle of a regular polygon = (n-2)*180 / n {n: no of sides of polygon)
No of sides from 3 - 10, we have following values of the internal angle
n = 3; angle: (3-2)*180 / 3 = 60
n = 4; angle: (4-2)*180 / 4 =90
n = 5; angle: 3*180 / 5 = 108
n = 6; angle: 4*180 / 6 = 120, greater than 110
its clear that with n = 7, 8, 9 and 10; internal angle value is greater than 110
the probability that the internal angles will be greater than 110 = (no of polygon with angle > 110) / total polygons
no of the polygon with angle > 110: 5 {with sides 6-10}
the probability that the internal angles will be greater than 110 = 5/8
Ans: E
No of sides from 3 - 10, we have following values of the internal angle
n = 3; angle: (3-2)*180 / 3 = 60
n = 4; angle: (4-2)*180 / 4 =90
n = 5; angle: 3*180 / 5 = 108
n = 6; angle: 4*180 / 6 = 120, greater than 110
its clear that with n = 7, 8, 9 and 10; internal angle value is greater than 110
the probability that the internal angles will be greater than 110 = (no of polygon with angle > 110) / total polygons
no of the polygon with angle > 110: 5 {with sides 6-10}
the probability that the internal angles will be greater than 110 = 5/8
Ans: E
gmatclubot
Re: The probability of drawing a regular polygon [#permalink]
25 May 2020, 15:08
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