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Exponents question
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23 Nov 2015, 16:08
23 Nov 2015, 16:08
2
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Question Stats:
81% (00:41) correct
18% (01:45) wrong based on 11 sessions
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Hi all, so I have a question on this exponents question.
Quant A: (5^x)/(5^(x-1))
Quant B: (5^(x-1))/(5^(x-2))
x>0
The answer is that two quantities are equal.
I understand that A: 5^(x-x+1)=5 and B: 5^(x-1-x+2)=5, thus A and B are equal, but what about the case where x=1?
Then A would be 5 over zero, and B would be zero over 1/5. In this case, A and B are not equal. So should the relationship be indeterminable?
Quant A: (5^x)/(5^(x-1))
Quant B: (5^(x-1))/(5^(x-2))
x>0
The answer is that two quantities are equal.
I understand that A: 5^(x-x+1)=5 and B: 5^(x-1-x+2)=5, thus A and B are equal, but what about the case where x=1?
Then A would be 5 over zero, and B would be zero over 1/5. In this case, A and B are not equal. So should the relationship be indeterminable?
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Re: Exponents question
[#permalink]
23 Nov 2015, 16:52
23 Nov 2015, 16:52
Expert Reply
Estrella wrote:
Hi all, so I have a question on this exponents question.
Quant A: (5^x)/(5^(x-1))
Quant B: (5^(x-1))/(5^(x-2))
x>0
The answer is that two quantities are equal.
I understand that A: 5^(x-x+1)=5 and B: 5^(x-1-x+2)=5, thus A and B are equal, but what about the case where x=1?
Then A would be 5 over zero, and B would be zero over 1/5. In this case, A and B are not equal. So should the relationship be indeterminable?
Quant A: (5^x)/(5^(x-1))
Quant B: (5^(x-1))/(5^(x-2))
x>0
The answer is that two quantities are equal.
I understand that A: 5^(x-x+1)=5 and B: 5^(x-1-x+2)=5, thus A and B are equal, but what about the case where x=1?
Then A would be 5 over zero, and B would be zero over 1/5. In this case, A and B are not equal. So should the relationship be indeterminable?
Hey Estrella,
\(5^0=1\) not 0 so even if x=1 the equality holds.
Regards,
