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GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
If 0 < x < 1, what is the median of the values x, x^-1, x^2,
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10 Dec 2022, 02:08
10 Dec 2022, 02:08
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Question Stats:
80% (01:09) correct
20% (02:27) wrong based on 15 sessions
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If 0 < x < 1, what is the median of the values \(x\), \(x^{-1}\), \(x^2\), \(\sqrt{x}\) and \(x^3\)?
A. \(x\)
B. \(x^{-1}\)
C. \(x^2\)
D. \(\sqrt{x}\)
E. \(x^3\)
A. \(x\)
B. \(x^{-1}\)
C. \(x^2\)
D. \(\sqrt{x}\)
E. \(x^3\)
Re: If 0 < x < 1, what is the median of the values x, x^-1, x^2,
[#permalink]
11 Dec 2022, 14:05
11 Dec 2022, 14:05
1
Expert Reply
x is a positive fraction. Pick any number, say 1/4
then
x = 1/4
x^-1 = 1/x = 4
x^2 = 1/16
x^1/2 = 1/2
x^3 = 1/64
Rearranging in ascending order:
x^3, x^2, x, x^1/2, x^-1
Median = x
Ans A
then
x = 1/4
x^-1 = 1/x = 4
x^2 = 1/16
x^1/2 = 1/2
x^3 = 1/64
Rearranging in ascending order:
x^3, x^2, x, x^1/2, x^-1
Median = x
Ans A
Re: If 0 < x < 1, what is the median of the values x, x^-1, x^2,
[#permalink]
21 Mar 2025, 15:48
21 Mar 2025, 15:48
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