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If 4 identical taps can fill a 100 liter tank in 6 hours, then how man
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16 Jun 2025, 05:26
16 Jun 2025, 05:26
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If 4 identical taps can fill a 100 liter tank in 6 hours, then how many hours will be required to fill a 150 liter tank by 8 such taps? (Note : Inlet flow rate of each tap is same)
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4.5 hours
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Re: If 4 identical taps can fill a 100 liter tank in 6 hours, then how man
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16 Jun 2025, 06:27
16 Jun 2025, 06:27
2
as we know work =Rate*time,
100=R{rate of 4 tapes}*6,
Rate of 4 tapes=100/6,
Rate of 1 tape=100/6*4=100/24,
now considering new work,
150=Rate of 8 tapes * T,
150=8*100/24 * T,
on solving we will get T=4.5 Hrs
100=R{rate of 4 tapes}*6,
Rate of 4 tapes=100/6,
Rate of 1 tape=100/6*4=100/24,
now considering new work,
150=Rate of 8 tapes * T,
150=8*100/24 * T,
on solving we will get T=4.5 Hrs
Re: If 4 identical taps can fill a 100 liter tank in 6 hours, then how man
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18 Jun 2025, 04:15
18 Jun 2025, 04:15
Expert Reply
Step 1: Find the filling rate of one tap.
- 4 taps fill 100 liters in 6 hours.
- So, 1 tap fills 100 liters in $4 \times 6=24$ hours.
- The rate of 1 tap is 100 liters $/ 24$ hours $=25 / 6$ liters $/$ hour .
Step 2: Find the filling rate of 8 taps.
- The rate of 1 tap is $25 / 6$ liters/hour.
- The rate of 8 taps is $8 \times(25 / 6)$ liters $/$ hour $=200 / 6$ liters $/$ hour $=100 / 3$ liters $/$ hour .
Step 3: Calculate the time required for 8 taps to fill a 150-liter tank.
- Time $=$ Total Volume $/$ Combined Rate
- Time $=150$ liters $/(100 / 3$ liters $/$ hour $)$
- Time $=150 \times(3 / 100)$ hours
- Time $=450 / 100$ hours
- Time $=4.5$ hours
- 4 taps fill 100 liters in 6 hours.
- So, 1 tap fills 100 liters in $4 \times 6=24$ hours.
- The rate of 1 tap is 100 liters $/ 24$ hours $=25 / 6$ liters $/$ hour .
Step 2: Find the filling rate of 8 taps.
- The rate of 1 tap is $25 / 6$ liters/hour.
- The rate of 8 taps is $8 \times(25 / 6)$ liters $/$ hour $=200 / 6$ liters $/$ hour $=100 / 3$ liters $/$ hour .
Step 3: Calculate the time required for 8 taps to fill a 150-liter tank.
- Time $=$ Total Volume $/$ Combined Rate
- Time $=150$ liters $/(100 / 3$ liters $/$ hour $)$
- Time $=150 \times(3 / 100)$ hours
- Time $=450 / 100$ hours
- Time $=4.5$ hours
