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If a, b, and c are consecutive positive integers where a < b
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22 Jun 2020, 09:34
22 Jun 2020, 09:34
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Question Stats:
88% (01:23) correct
11% (00:48) wrong based on 44 sessions
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If a, b, and c are consecutive positive integers where a < b < c, and c - a = 16/b, then a + b + c =
A. 30
B. 24
C. 18
D. 12
E. 6
A. 30
B. 24
C. 18
D. 12
E. 6
Re: If a, b, and c are consecutive positive integers where a < b
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22 Jun 2020, 09:34
22 Jun 2020, 09:34
Expert Reply
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Re: If a, b, and c are consecutive positive integers where a < b
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22 Jun 2020, 09:58
22 Jun 2020, 09:58
Carcass wrote:
If a, b, and c are consecutive positive integers where a < b < c, and c - a = 16/b, then a + b + c =
A. 30
B. 24
C. 18
D. 12
E. 6
A. 30
B. 24
C. 18
D. 12
E. 6
If a, b, and c are consecutive positive integers where a < b < c, then we know that:
a + 1 = b
And, more importantly, a + 2 = c
If a + 2 = c, then c - a = 2
GIVEN: c - a = 16/b
Substitute to get: 2 = 16/b
Solve: b = 8
So, a, b and c equal 7, 8, and 9 respectively
This means a + b + c = 7 + 8+ 9 = 24
Answer: B
Cheers,
Brent
