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If all the students from Creede, and only those students, ar
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25 Jul 2020, 04:53
25 Jul 2020, 04:53
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If all the students from Creede, and only those students, are earning A’s and the rest of the grades are evenly distributed among students in the other subdistricts, approximately how many students from Bayfield are earning B’s?
50
75
150
225
306
Re: If all the students from Creede, and only those students, ar
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29 Jul 2020, 23:02
29 Jul 2020, 23:02
1
Question: If all the students from Creede, and only those students, are earning A’s and the rest of the grades are evenly distributed among students in the other subdistricts, approximately how many students from Bayfield are earning B’s?
Answer: Only students from Creede are getting A's so Subtract Creede students from Total
1105 - 211 = 894
Now we have to calculate How many students from Bayfield will get B?
We know that 450 students will get B grade (check fig 2)
450/894 = 0.5 (approx)
Total students from Bayfield: 306 (fig 1)
306 * 0.5 = 153 (approx 150) option C
Answer: Only students from Creede are getting A's so Subtract Creede students from Total
1105 - 211 = 894
Now we have to calculate How many students from Bayfield will get B?
We know that 450 students will get B grade (check fig 2)
450/894 = 0.5 (approx)
Total students from Bayfield: 306 (fig 1)
306 * 0.5 = 153 (approx 150) option C
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Joined: 25 Jul 2020
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GRE 1: Q170 V157
Re: If all the students from Creede, and only those students, ar
[#permalink]
25 Jul 2020, 11:23
25 Jul 2020, 11:23
With 211 students earning A, it's safe to assume that a negligible (if at all!) number of students from other districts will get an A. Hence we need to find the proportion of Bs:
(B)/(B + C + D + E), which is about 0.5.
Hence the answer is 306/2, or roughly 150. Answer is C.
(B)/(B + C + D + E), which is about 0.5.
Hence the answer is 306/2, or roughly 150. Answer is C.
