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If erasers cost $0.25 each, at most how many erasers can be
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11 Dec 2020, 22:22
11 Dec 2020, 22:22
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Question Stats:
60% (00:38) correct
40% (01:33) wrong based on 20 sessions
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If erasers cost $0.25 each, at most how many erasers can be purchased for n dollars, where n is an integer?
A. n/25
B. n/4
C. 4n
D. 25n
E. 25n/4
A. n/25
B. n/4
C. 4n
D. 25n
E. 25n/4
Re: If erasers cost $0.25 each, at most how many erasers can be
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12 Dec 2020, 05:24
12 Dec 2020, 05:24
1
Carcass wrote:
If erasers cost $0.25 each, at most how many erasers can be purchased for n dollars, where n is an integer?
A. n/25
B. n/4
C. 4n
D. 25n
E. 25n/4
A. n/25
B. n/4
C. 4n
D. 25n
E. 25n/4
Explanation:
If one eraser cost $0.25 then eraser can be purchased for n dollars will be = \(\frac{n}{0.25} = 4n\)
*** If there is confusion with "n dollars" just convert n = $1 and check how many eraser can be purchased for $1 ?
just divide = \(\frac{1}{0.25} \)= 4 eraser
Re: If erasers cost $0.25 each, at most how many erasers can be
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17 Dec 2020, 19:28
17 Dec 2020, 19:28
$0.25 ==> 1 pencil /.25 ==> 4 pencils / 1
