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Re: If Mary has half as many cents as Nora has dollars, then No [#permalink]
As algebraic approach I would do the following:

"If Mary has half as many cents as Nora has dollars"


M = (1/2)*(N/100) - I divided by 100 because I need to 'equalize' cents Mary with cents Nora
M = N/200
N = 200M

"(...) then Nora has what percent more cents than Mary does? (100 cents = 1 dollar)"

"what percent more than" - is an "alert" that I need use the "percent greater than" formula:
(N - M)/M x 100%


so,
(200M - M)/M x 100% =
199/M x 100% =
19,900%

Answer D
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If Mary has half as many cents as Nora has dollars, then No [#permalink]
Let's say Nora has `x` dollars, which is equivalent to `100x` cents. Mary has half as many cents as Nora has dollars, so Mary has `(1/2)x` cents. The difference between the number of cents Nora and Mary have is `100x - (1/2)x = (199/2)x`. To find the percentage difference, we divide the difference by the number of cents Mary has and multiply by 100: `((199/2)x / (1/x)) * 100 = 19900%`. So, the answer is (D) 19,900%.
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Re: If Mary has half as many cents as Nora has dollars, then No [#permalink]
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Re: If Mary has half as many cents as Nora has dollars, then No [#permalink]
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