GeminiHeat wrote:
If one student is chosen randomly out of a group of seven students, then one student is again chosen randomly from the same group of seven, what is the probability that two different students will be chosen?
(A) 36/49
(B) 6/7
(C) 19/21
(D) 13/14
(E) 48/49
Not a fan of this question.  Choosing the first student is always 1/7, right?  Ok.  So then this is a "with replacement" question because you're picking again from the same set of 7.  A different student from the first one chosen would be 6 out of 7, right?  yes.  So why isn't the answer 1/7 X 6/7 = 6/49.  Makes no sense.  Fortunately, because I don't see the answer, I would have guessed 6/7 anyway because that was part of my solution.  Don't like this question at all (the source is "others,please specify," so it figures)