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If the integer a is a multiple of 6, the integer b is a mult
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07 Apr 2018, 19:24
07 Apr 2018, 19:24
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Question Stats:
80% (01:18) correct
19% (01:51) wrong based on 21 sessions
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If the integer a is a multiple of 6, the integer b is a multiple of 3, and a>b>0, then which of the following integers must be \(a^2\) – \(b^2\) multiple of?
A)6
B)8
c)9
D)10
E)12
A)6
B)8
c)9
D)10
E)12
Re: If the integer a is a multiple of 6, the integer b is a mult
[#permalink]
07 Apr 2018, 21:56
07 Apr 2018, 21:56
On substituting the values of 6 and 3 in a and b,
a^2 – b^2 = 6^2 - 3^2 = 36-9
=27
27 is a multiple of only 9 in the answer options.
So C
a^2 – b^2 = 6^2 - 3^2 = 36-9
=27
27 is a multiple of only 9 in the answer options.
So C
gmatclubot
Re: If the integer a is a multiple of 6, the integer b is a mult [#permalink]
07 Apr 2018, 21:56
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