The midpoint of (a, b) and (c, d) = [(a+c)/2, (b+d)/2]

Given: Point A is the midpoint between points (5,8) and (-3, -2)
So, the coordinates of point A = [(5 + -3)/2, (8 + -2)/2] = (2/2, 6/2) = (1, 3)

Given: The midpoint between point A and point B is (4, -1)
So, we don't know the coordinates of point B
Let the coordinates of point B = (x, y)

Applying the formula, we get: [(1 + x)/2, (3 + y)/2] = (4, -1)
This means (1 + x)/2 = 4
Solve to get: x = 7

It also means (3 + y)/2 = -1
Solve to get: y = -5

So, the coordinates of point B = (7, -5)
So, point B is in quadrant IV



Answer: D