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In the figure above, the circle is inscribed in the square.
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06 Oct 2018, 15:59
06 Oct 2018, 15:59
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95% (00:33) correct
5% (01:04) wrong based on 80 sessions
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In the figure above, the circle is inscribed in the square.
The area of the circle is \(9\pi\).
Quantity A |
Quantity B |
The area of the square |
\(30\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: In the figure above, the circle is inscribed in the square.
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12 Jan 2019, 06:27
12 Jan 2019, 06:27
πr^2=9
r=3 (since r is not negative)
2r=2*3=6
Area of square = 6^2 = 36
Answer A
r=3 (since r is not negative)
2r=2*3=6
Area of square = 6^2 = 36
Answer A
In the figure above, the circle is inscribed in the square.
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04 Jan 2024, 20:51
04 Jan 2024, 20:51
1
The area of the circle is \(9\pi\)
\(\pi r^2 = 9\pi\)
\(r^2 = 9\)
\(r = 3\)
Twice the radius is \(6\) and will give the diameter of the circle as well as the length of any side of the square.
Therefore the area of the square will be \(6 \times 6 = 36\)
Quantity A is greater than B
\(\pi r^2 = 9\pi\)
\(r^2 = 9\)
\(r = 3\)
Twice the radius is \(6\) and will give the diameter of the circle as well as the length of any side of the square.
Therefore the area of the square will be \(6 \times 6 = 36\)
Quantity A is greater than B
