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In the preceding figure, ABCD is a square and AC = BD = 12
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05 Oct 2021, 07:59
05 Oct 2021, 07:59
Expert Reply
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Question Stats:
90% (00:52) correct
9% (00:25) wrong based on 22 sessions
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GRE In the preceding figure, ABCD is a square and AC = BD = 12.jpg [ 14.32 KiB | Viewed 1376 times ]
In the preceding figure, ABCD is a square and AC = BD = 12
Quantity A |
Quantity B |
The length of a side of the square |
6 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Re: In the preceding figure, ABCD is a square and AC = BD = 12
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05 Oct 2021, 10:19
05 Oct 2021, 10:19
1
Carcass wrote:
Attachment:
GRE In the preceding figure, ABCD is a square and AC = BD = 12.jpg
In the preceding figure, ABCD is a square and AC = BD = 12
Quantity A |
Quantity B |
The length of a side of the square |
6 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Relation btwn side (a) and diagonal (d) of a square : \(d = a\sqrt{2}\)
\(a = \frac{12}{\sqrt{2}} = \frac{12}{1.414} > 6\)
Answer is A)
gmatclubot
Re: In the preceding figure, ABCD is a square and AC = BD = 12 [#permalink]
05 Oct 2021, 10:19
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