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In the preceding figure, what is the value of x?
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07 Nov 2021, 16:19
07 Nov 2021, 16:19
Expert Reply
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Question Stats:
80% (01:38) correct
20% (02:25) wrong based on 10 sessions
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In the preceding figure, A and B are regular polygons and lines \(\ell\) and \(m\) are parallel. What is the value of x?
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48
In the preceding figure, what is the value of x?
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11 Nov 2021, 00:45
11 Nov 2021, 00:45
explanation please, that why we cannot use pentagon for solving this question?
In the preceding figure, what is the value of x?
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11 Nov 2021, 06:20
11 Nov 2021, 06:20
Since they are regular polygons all their internal angles are equals
Internal Angle of Pentagon = \(108^o\)
Internal Angle of Hexagon = \(120^o\)
Triangle formed by the line m, the Hexagon and line connecting the two polygons is an equilateral triangle.
Its hard to explain since the diagram hasn't named the points.
Now, the triangle formed by line l, the Pentagon and line connecting the two polygons -
The angle just above \(x\) is equal to \(180^o - 108^o = 72^o\)
The angle formed by intersection of line l and joining-line will be \(60^o\)
So \(x^o + 72^o + 60^o = 180^o\)
\(x^o = 180^o - 132^o = \) \(48^o\)
Internal Angle of Pentagon = \(108^o\)
Internal Angle of Hexagon = \(120^o\)
Triangle formed by the line m, the Hexagon and line connecting the two polygons is an equilateral triangle.
Its hard to explain since the diagram hasn't named the points.
Now, the triangle formed by line l, the Pentagon and line connecting the two polygons -
The angle just above \(x\) is equal to \(180^o - 108^o = 72^o\)
The angle formed by intersection of line l and joining-line will be \(60^o\)
So \(x^o + 72^o + 60^o = 180^o\)
\(x^o = 180^o - 132^o = \) \(48^o\)
