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In the triangle
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19 Mar 2020, 11:21
19 Mar 2020, 11:21
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Question Stats:
81% (00:25) correct
18% (00:25) wrong based on 72 sessions
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Attachment:
#greprepclub In the triangle.jpg [ 26.99 KiB | Viewed 2688 times ]
Quantity A |
Quantity B |
\(x\) |
\(5 \sqrt{2}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Re: In the triangle
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09 Apr 2020, 19:46
09 Apr 2020, 19:46
1
Carcass wrote:
Attachment:
#greprepclub In the triangle.jpg
Quantity A |
Quantity B |
\(x\) |
\(5 \sqrt{2}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Here,
in the right angled \triangle
By Pythagoras theorem,
x = \(\sqrt{{10}^2 - {5}^2} = \sqrt{75} = 5\sqrt{3}\)
Re: In the triangle
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12 Apr 2020, 02:50
12 Apr 2020, 02:50
pranab223 wrote:
Carcass wrote:
Attachment:
#greprepclub In the triangle.jpg
Quantity A |
Quantity B |
\(x\) |
\(5 \sqrt{2}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Here,
in the right angled \triangle
By Pythagoras theorem,
x = \(\sqrt{{10}^2 - {5}^2} = \sqrt{75} = 5\sqrt{3}\)
your wrong.. it should be 5 root 3.
