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Issue with OA of Q#5 of Quant Test#10 greprepclub
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20 Aug 2016, 07:29
20 Aug 2016, 07:29
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100% (01:26) wrong based on 2 sessions
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ABCD is a rectangle.R is the mid-point of DC
Quantity A : Area of Triangle DPC
Quantity B : Twice the Area of Triangle DQR
The answer provided is D,while I have calculated it to be C i.e. both the quantities are equal.Here is my solution of this problem:
Quantity A : Area of Triangle DPC = 1/2(DC)*(BC)
Quantity B : Twice the Area of Triangle DQR = 2 *[1/2(DC/2)*(BC)] = 2 *[1/2(DR)*(BC)] = Area of Triangle DPC = 1/2(DC)*(BC)
So quantity A is equal to Quantity B therefore answer is C
Source : http://gre.myprepclub.com/tests/results/3104/Q02-83
Quantity A : Area of Triangle DPC
Quantity B : Twice the Area of Triangle DQR
The answer provided is D,while I have calculated it to be C i.e. both the quantities are equal.Here is my solution of this problem:
Quantity A : Area of Triangle DPC = 1/2(DC)*(BC)
Quantity B : Twice the Area of Triangle DQR = 2 *[1/2(DC/2)*(BC)] = 2 *[1/2(DR)*(BC)] = Area of Triangle DPC = 1/2(DC)*(BC)
So quantity A is equal to Quantity B therefore answer is C
Source : http://gre.myprepclub.com/tests/results/3104/Q02-83
Re: Issue with OA of Q#5 of Quant Test#10 greprepclub
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22 Aug 2016, 04:05
22 Aug 2016, 04:05
We know nothing about P and it does not matter here;because
Area of Triangle = (1/2)*(Base)*(Height)
So here Height or Altitude of both Triangles is BC=AD
Base of Triangle DPC = DC
Base of Triangle DQR = (DC)/2 = DR
as R is given to be the mid-point of DC
regards
m.yasir
Area of Triangle = (1/2)*(Base)*(Height)
So here Height or Altitude of both Triangles is BC=AD
Base of Triangle DPC = DC
Base of Triangle DQR = (DC)/2 = DR
as R is given to be the mid-point of DC
regards
m.yasir
