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Jhon bought an ordinary mobile and a cover for $ 2000. Prince bought a
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05 Apr 2021, 07:31
05 Apr 2021, 07:31
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Jhon bought an ordinary mobile and a cover for $ 2000. Prince bought a smart phone and the same cover for $ 2000 more than what Jhon had paid. The price of the cover was one tenth of the combined cost of 2 mobiles. what is the cost of the ordinary mobile?
A) $1000
B) $1200
C) $1500
D) $1600
E)$1800
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
A) $1000
B) $1200
C) $1500
D) $1600
E)$1800
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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Joined: 10 Apr 2015
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Re: Jhon bought an ordinary mobile and a cover for $ 2000. Prince bought a
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05 Apr 2021, 07:49
05 Apr 2021, 07:49
1
Carcass wrote:
Jhon bought an ordinary mobile and a cover for $ 2000. Prince bought a smart phone and the same cover for $ 2000 more than what Jhon had paid. The price of the cover was one tenth of the combined cost of 2 mobiles. what is the cost of the ordinary mobile?
A) $1000
B) $1200
C) $1500
D) $1600
E)$1800
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
A) $1000
B) $1200
C) $1500
D) $1600
E)$1800
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Let M = cost of ordinary mobile
Let C = cost of the cover
Let S = cost of smart mobile
Jhon bought an ordinary mobile and a cover for $ 2000
We get: M + C = 2000
Prince bought a smart phone and the same cover for $ 2000 more than what Jhon had paid.
We get: S + C = 4000
The price of the cover was one tenth of the combined cost of 2 mobiles. what is the cost of the ordinary mobile?
We get: C = 1/10(M + S)
Multiply both sides by 10 to get: 10C = M + S
Lots of options from here. Here's one approach:
Take:
M + C = 2000
S + C = 4000
ADD them to get: M + S + 2C = 6000
Replace M + S with 10C to get: 10C + 2C = 6000
Simplify: 12C = 6000
Solve: C = 6000/12 = 500
We already know that M + C = 2000
Since C = 500, we can see that M = 1500
Answer: C
Cheers,
Brent
Re: Jhon bought an ordinary mobile and a cover for $ 2000. Prince bought a
[#permalink]
06 Apr 2021, 10:29
06 Apr 2021, 10:29
1
m+c=2000----(1)
s+c=4000-----(2)
And,m+s=10c
(1)+(2)
m+c+s+c=2000+4000
=>m+s+2c=6000
=>10c+2c=6000
=>12c=6000
=>c=500
So,cost of mobile =2000-500=1500(Ans)
s+c=4000-----(2)
And,m+s=10c
(1)+(2)
m+c+s+c=2000+4000
=>m+s+2c=6000
=>10c+2c=6000
=>12c=6000
=>c=500
So,cost of mobile =2000-500=1500(Ans)
