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Let C and K be constants. If x^2 + Kx+ 5 factors into
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25 Mar 2019, 11:42
25 Mar 2019, 11:42
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Question Stats:
85% (00:28) correct
14% (00:36) wrong based on 7 sessions
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Let C and K be constants. If \(x^2 + Kx+ 5\) factors into (x + 1)(x + C), the value of K is
(A) 0
(B) 5
(C) 6
(D) 8
(E) not enough information
(A) 0
(B) 5
(C) 6
(D) 8
(E) not enough information
Re: Let C and K be constants. If x^2 + Kx+ 5 factors into
[#permalink]
28 Mar 2019, 00:00
28 Mar 2019, 00:00
1
the factors of +5 are 1 and 5 or -1 and -5.
we have been provided with the factors for the given eqn and among the two factors one of them is \((x+1)\) therefore the other factor must be \((x+5)\) and not \((x-5)\) therefore the value of c = 5.
If you expand the two factors by multiplying and compare it with the given eqn k = 6.
\((x+1)(x+5) = x^2 +5x +x + 5 = x^2 +6x+5\) where k=6
we have been provided with the factors for the given eqn and among the two factors one of them is \((x+1)\) therefore the other factor must be \((x+5)\) and not \((x-5)\) therefore the value of c = 5.
If you expand the two factors by multiplying and compare it with the given eqn k = 6.
\((x+1)(x+5) = x^2 +5x +x + 5 = x^2 +6x+5\) where k=6
gmatclubot
Re: Let C and K be constants. If x^2 + Kx+ 5 factors into [#permalink]
28 Mar 2019, 00:00
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