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Let ♠ x be defined by the equation ♠
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01 Feb 2022, 04:45
01 Feb 2022, 04:45
Expert Reply
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Question Stats:
93% (00:32) correct
6% (00:37) wrong based on 16 sessions
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If \(x \neq zero\) , let ♠ x be defined by the equation ♠ \(x = x-\frac{1}{x}\). Then ♠ (-3) =
A - 10/3
B - 8/3
C 0
D 8/3
E 10/3
A - 10/3
B - 8/3
C 0
D 8/3
E 10/3
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Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Let ♠ x be defined by the equation ♠
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03 Feb 2022, 12:16
03 Feb 2022, 12:16
1
Carcass wrote:
If \(x \neq zero\) , let ♠ x be defined by the equation ♠ \(x = x-\frac{1}{x}\). Then ♠ (-3) =
A - 10/3
B - 8/3
C 0
D 8/3
E 10/3
A - 10/3
B - 8/3
C 0
D 8/3
E 10/3
Given: ♠ \(x = x-\frac{1}{x}\)
So, ♠ \(-3 = (-3)-\frac{1}{-3}=(-3)-(-\frac{1}{3})=(-3)+ \frac{1}{3}=\frac{-9}{3}+ \frac{1}{3}= \frac{-8}{3}= -\frac{8}{3}\)
Answer: B
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Let x be defined by the equation
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08 Aug 2022, 00:07
08 Aug 2022, 00:07
1
Given that ♠ \(x = x-\frac{1}{x}\) and we need to find the value of ♠ (-3)
To find ♠ (-3) we need to compare what is after ♠ in ♠ (-3) and ♠ x
=> We need to substitute x with -3 in ♠ \(x = x-\frac{1}{x}\) to get the value of ♠ (-3)
=> ♠ \(-3 = -3 - \frac{1}{(-3)}\) = \( -3 + \frac{1}{3}\) = \(\frac{-9 + 1 }{3}\) = \(\frac{-8}{3}\)
So, Answer will be B
Hope it helps!
Watch the following video to learn the Basics of Functions and Custom Characters
To find ♠ (-3) we need to compare what is after ♠ in ♠ (-3) and ♠ x
=> We need to substitute x with -3 in ♠ \(x = x-\frac{1}{x}\) to get the value of ♠ (-3)
=> ♠ \(-3 = -3 - \frac{1}{(-3)}\) = \( -3 + \frac{1}{3}\) = \(\frac{-9 + 1 }{3}\) = \(\frac{-8}{3}\)
So, Answer will be B
Hope it helps!
Watch the following video to learn the Basics of Functions and Custom Characters
