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n = 0.00025 × 10^4 and m = 0.005 × 10^2
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25 Aug 2018, 15:05
25 Aug 2018, 15:05
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\(n = 0.00025 \times 10^4\) and \(m = 0.005 \times 10^2\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(\frac{n}{m}\) |
\(0.5\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
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Re: n = 0.00025 × 10^4 and m = 0.005 × 10^2
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29 Aug 2018, 07:04
29 Aug 2018, 07:04
1
sandy wrote:
\(n = 0.00025 \times 10^4\) and \(m = 0.005 \times 10^2\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(\frac{n}{m}\) |
\(0.5\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
GIVEN: n = 0.00025 x 10^4
Move the decimal point 4 spaces to the RIGHT to get: n = 2.5
GIVEN: m = 0.005 x 10^2
Move the decimal point 2 spaces to the RIGHT to get: m = 0.5
We get:
Quantity A: 2.5/0.5
Quantity B: 0.5
Evaluate:
Quantity A: 5
Quantity B: 0.5
Answer: A
Re: n = 0.00025 × 10^4 and m = 0.005 × 10^2
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20 Aug 2020, 20:18
20 Aug 2020, 20:18
1
0.00025*10^4 / 0.005*10^2 = (25*10^-5)*10^4/(5*10^-3)*10^2
=(25/5)*(10^-5+4)/10^-3+2
=5*10/10=5
=(25/5)*(10^-5+4)/10^-3+2
=5*10/10=5
