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No of 3 digit passwords that can be formed using different
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Updated on: 23 Oct 2020, 09:55
Updated on: 23 Oct 2020, 09:55
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Question Stats:
40% (01:48) correct
60% (01:19) wrong based on 50 sessions
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Quantity A |
Quantity B |
No of 3 digit passwords that can be formed using different digits from 1, 2, 3, 4, 5, so that the digits are in increasing order from left to right |
10 |
a. Quantity A is greater.
b. Quantity B is greater.
c. The two quantities are equal.
d. The relationship cannot be determined from the information given.
Originally posted by arunkumarzz on 23 Oct 2020, 08:49.
Last edited by Carcass on 23 Oct 2020, 09:55, edited 2 times in total.
Last edited by Carcass on 23 Oct 2020, 09:55, edited 2 times in total.
Formatted
Re: No of 3 digit passwords that can be formed using different
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23 Oct 2020, 09:07
23 Oct 2020, 09:07
2
I don't know if there is a faster way to solve this problem, but here is I how I solved it:
Divide into cases:
First two numbers are 1 and 2.
There are three possible numbers for the third number (3,4,5). We have 3 cases here.
First two numbers are 1 and 3:
There are two possible numbers for the third number(4,5). We have 2 cases here.
First two numbers are 1 and 4:
Just one possible number for the third number(5). 1 case
First two numbers are 2 and 3:
Two possible numbers for the third number (4,5). 2 cases
First two numbers are 2 and 4:
Just one possible number for the third number (5). 1 case
The last case is the first is formed by the sequence 3-4-5.
We have 3+2+1+2+1+1=10 possibilities. Answer is C
Divide into cases:
First two numbers are 1 and 2.
There are three possible numbers for the third number (3,4,5). We have 3 cases here.
First two numbers are 1 and 3:
There are two possible numbers for the third number(4,5). We have 2 cases here.
First two numbers are 1 and 4:
Just one possible number for the third number(5). 1 case
First two numbers are 2 and 3:
Two possible numbers for the third number (4,5). 2 cases
First two numbers are 2 and 4:
Just one possible number for the third number (5). 1 case
The last case is the first is formed by the sequence 3-4-5.
We have 3+2+1+2+1+1=10 possibilities. Answer is C
Re: No of 3 digit passwords that can be formed using different
[#permalink]
23 Oct 2020, 09:56
23 Oct 2020, 09:56
1
Expert Reply
Please, Please, follow the rules how to format a question: QCQ
It is very easy and took one second
https://gre.myprepclub.com/forum/how-to-po ... 12752.html
It is very easy and took one second
https://gre.myprepclub.com/forum/how-to-po ... 12752.html
