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-1<x<0
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01 Oct 2022, 09:57
01 Oct 2022, 09:57
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18% (00:37) correct
81% (00:39) wrong based on 44 sessions
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\(-1<x<0\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(-x\) |
\(-x^3\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Part of the Skill Builder Project
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials
GRE Geometry Formulas
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials
GRE Geometry Formulas
GRE - Math Book
Re: -1<x<0
[#permalink]
03 Oct 2022, 10:08
03 Oct 2022, 10:08
Could someone please explain this question?
I got A as I divided both sides by (-x)
Hence,
A: 1
B: x^2
Now since x is less than 0 but greater than (-1), hence x^2 is less than (1)
Hence, A
But since the answer is B, what is wrong with my approach?
I got A as I divided both sides by (-x)
Hence,
A: 1
B: x^2
Now since x is less than 0 but greater than (-1), hence x^2 is less than (1)
Hence, A
But since the answer is B, what is wrong with my approach?
Re: -1<x<0
[#permalink]
12 Oct 2022, 00:14
12 Oct 2022, 00:14
1
-1 < x <0 is basically saying
x= negative non integer or fraction
Let x= -1/2
Quantity A
-1/2 or -0.5
Quantity B
(-1/2)(-1/2)(-1/2) = -1/8 or -0.125
Quantity A is more negative than Quantity B
Hence B is greater
Posted from my mobile device
x= negative non integer or fraction
Let x= -1/2
Quantity A
-1/2 or -0.5
Quantity B
(-1/2)(-1/2)(-1/2) = -1/8 or -0.125
Quantity A is more negative than Quantity B
Hence B is greater
Posted from my mobile device
