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For positive numbers p and q,
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30 Sep 2022, 03:23
30 Sep 2022, 03:23
Expert Reply
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Question Stats:
92% (01:05) correct
8% (00:45) wrong based on 25 sessions
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For positive numbers p and q, \(\frac{p+q}{p}=\frac{10}{7}
\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
\)
Quantity A |
Quantity B |
\( \frac{p-q}{q}\) |
\(\frac{5}{3 }\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Joined: 02 Jan 2020
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Re: For positive numbers p and q,
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30 Sep 2022, 09:22
30 Sep 2022, 09:22
1
Given that \(\frac{p+q}{p}=\frac{10}{7}\)
=> \(\frac{p}{p}\) + \(\frac{q}{p}\) = \(\frac{10}{7}\)
=> 1 + \(\frac{q}{p}\) = \(\frac{10}{7}\)
=> \(\frac{q}{p}\) = \(\frac{10}{7}\) - 1 = \(\frac{10-7}{7}\) = \(\frac{3}{7}\)
=> \(\frac{p}{q}\) = \(\frac{7}{3}\)
Quantity A = \(\frac{p-q}{q}\) = \(\frac{p}{q}\) - \(\frac{q}{q}\) = \(\frac{7}{3}\) - 1 = \(\frac{7-3}{3}\) = \(\frac{4}{3}\)
Clearly Quantity B(\(\frac{5}{3 }\)) > Quantity A(\(\frac{4}{3}\))
So, Answer will be B
Hope it helps!
=> \(\frac{p}{p}\) + \(\frac{q}{p}\) = \(\frac{10}{7}\)
=> 1 + \(\frac{q}{p}\) = \(\frac{10}{7}\)
=> \(\frac{q}{p}\) = \(\frac{10}{7}\) - 1 = \(\frac{10-7}{7}\) = \(\frac{3}{7}\)
=> \(\frac{p}{q}\) = \(\frac{7}{3}\)
Quantity A = \(\frac{p-q}{q}\) = \(\frac{p}{q}\) - \(\frac{q}{q}\) = \(\frac{7}{3}\) - 1 = \(\frac{7-3}{3}\) = \(\frac{4}{3}\)
Clearly Quantity B(\(\frac{5}{3 }\)) > Quantity A(\(\frac{4}{3}\))
So, Answer will be B
Hope it helps!
For positive numbers p and q,
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11 Oct 2022, 00:56
11 Oct 2022, 00:56
1
More information in the stem for this one
(p + q)/p = (10/7) since LHS= RHS ,p=7
RHS fraction can’t be reduced any further
.: (7+3)/7 =(10/7) now q= 3
Quantity A
(7-3)/3 = 4/3
Quantity B
5/3
Very clear who wins here (B)
Posted from my mobile device
(p + q)/p = (10/7) since LHS= RHS ,p=7
RHS fraction can’t be reduced any further
.: (7+3)/7 =(10/7) now q= 3
Quantity A
(7-3)/3 = 4/3
Quantity B
5/3
Very clear who wins here (B)
Posted from my mobile device
