GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
In the xy-plane, the distance between the point P (1,3) and
[#permalink]
13 Oct 2020, 06:29
13 Oct 2020, 06:29
Expert Reply
00:00
Question Stats:
81% (01:13) correct
18% (02:09) wrong based on 43 sessions
Hide Show timer Statistics
In the xy-plane, the distance between the point P (1,3) and Q (9,y) is 17. If y > 0, then what is the value of y?
A. 15
B. 16
C. 17
D. 18
E. 19
Kudos for the right answer and explanation
A. 15
B. 16
C. 17
D. 18
E. 19
Kudos for the right answer and explanation
Re: In the xy-plane, the distance between the point P (1,3) and
[#permalink]
13 Oct 2020, 10:22
13 Oct 2020, 10:22
1
I plug the answer back to the question (starting from C)
Assume y =17
(1,3) (9,17)
Then the distance equal (17-3)^2 +(9-1)^2
225+64=289
Distance equal √289=17
Ans equal C
Posted from my mobile device
Assume y =17
(1,3) (9,17)
Then the distance equal (17-3)^2 +(9-1)^2
225+64=289
Distance equal √289=17
Ans equal C
Posted from my mobile device
In the xy-plane, the distance between the point P (1,3) and
[#permalink]
14 Oct 2022, 02:58
14 Oct 2022, 02:58
2
\(x^2 + 8^2 = 17^2\)
Then
\(x^2 = 289-64\)
So
\(x = \sqrt{225}=15\)
Since it started at y equals to 3 so 15+3 = 18
D
Then
\(x^2 = 289-64\)
So
\(x = \sqrt{225}=15\)
Since it started at y equals to 3 so 15+3 = 18
D
Attachments
IMG_14E330EA08C0-1.jpeg [ 172.23 KiB | Viewed 1615 times ]
