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GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2509
Given Kudos: 1058
GPA: 3.39
In the figures above if the area of the triangle on the right is twice
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18 Oct 2022, 06:45
18 Oct 2022, 06:45
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Question Stats:
33% (03:56) correct
66% (01:26) wrong based on 3 sessions
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In the figures above, if the area of the triangle on the right is twice the area of the triangle on the left, then in terms of s, S=
A. \(\frac{\sqrt{2}}{2}s\)
B. \(\frac{\sqrt{3}}{2}s\)
C. \(\sqrt{2}s\)
D. \(\sqrt{3}s\)
E. \(2s\)
Re: In the figures above if the area of the triangle on the right is twice
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22 Oct 2022, 07:50
22 Oct 2022, 07:50
Expert Reply
Since in the given triangles the three angles are identical then they are similar triangles.
Useful property of similar triangles: in two similar triangles, the ratio of their areas is the square of the ratio of their sides.
Hence \(\frac{AREA}{area}=\frac{S^2}{s^2}=2\) --> \(S=s\sqrt{2}\).
Answer: C.
Useful property of similar triangles: in two similar triangles, the ratio of their areas is the square of the ratio of their sides.
Hence \(\frac{AREA}{area}=\frac{S^2}{s^2}=2\) --> \(S=s\sqrt{2}\).
Answer: C.
gmatclubot
Re: In the figures above if the area of the triangle on the right is twice [#permalink]
22 Oct 2022, 07:50
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