GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
In the figures above if the area of the triangle on the right is twice
[#permalink]
18 Oct 2022, 06:45
18 Oct 2022, 06:45
1
Expert Reply
00:00
Question Stats:
33% (03:56) correct
66% (01:26) wrong based on 3 sessions
Hide Show timer Statistics
In the figures above, if the area of the triangle on the right is twice the area of the triangle on the left, then in terms of s, S=
A. \(\frac{\sqrt{2}}{2}s\)
B. \(\frac{\sqrt{3}}{2}s\)
C. \(\sqrt{2}s\)
D. \(\sqrt{3}s\)
E. \(2s\)
Re: In the figures above if the area of the triangle on the right is twice
[#permalink]
22 Oct 2022, 07:50
22 Oct 2022, 07:50
Expert Reply
Since in the given triangles the three angles are identical then they are similar triangles.
Useful property of similar triangles: in two similar triangles, the ratio of their areas is the square of the ratio of their sides.
Hence \(\frac{AREA}{area}=\frac{S^2}{s^2}=2\) --> \(S=s\sqrt{2}\).
Answer: C.
Useful property of similar triangles: in two similar triangles, the ratio of their areas is the square of the ratio of their sides.
Hence \(\frac{AREA}{area}=\frac{S^2}{s^2}=2\) --> \(S=s\sqrt{2}\).
Answer: C.
gmatclubot
Re: In the figures above if the area of the triangle on the right is twice [#permalink]
22 Oct 2022, 07:50
Moderators:
