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The average (arithmetic mean) of 3^2,3^4,3^6
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24 Oct 2022, 08:31
24 Oct 2022, 08:31
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Question Stats:
93% (01:02) correct
6% (01:07) wrong based on 29 sessions
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Quantity A |
Quantity B |
The average (arithmetic mean) of \(3^2,3^4,3^6\) |
\(3^4\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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GRE Math Essentials (2022)
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GRE Math Essentials (2022)
GRE Geometry Formulas
GRE - Math Book
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Re: The average (arithmetic mean) of 3^2,3^4,3^6
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25 Oct 2022, 00:42
25 Oct 2022, 00:42
1
============================================================
Theory
============================================================
Quantity A: The average (arithmetic mean) of \(3^2,3^4,3^6\)
=> Average = \(\frac{3^2 + 3^4 + 3^6}{3}\) = \(3 + 3^3 + 3^5\) > \(3^4\)
Clearly, Quantity A > Quantity B
So, Answer will be A.
Hope it helps!
Watch the following video to Learn the Basics of Statistics
Theory
- ‣‣‣ Average or Arithmetic Mean = (Sum Of All The Numbers) / (Total Number Of Numbers)
============================================================
Quantity A: The average (arithmetic mean) of \(3^2,3^4,3^6\)
=> Average = \(\frac{3^2 + 3^4 + 3^6}{3}\) = \(3 + 3^3 + 3^5\) > \(3^4\)
Clearly, Quantity A > Quantity B
So, Answer will be A.
Hope it helps!
Watch the following video to Learn the Basics of Statistics
Re: The average (arithmetic mean) of 3^2,3^4,3^6
[#permalink]
16 Apr 2025, 08:57
16 Apr 2025, 08:57
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