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The average (arithmetic mean) of 3^2,3^4,3^6

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The average (arithmetic mean) of 3^2,3^4,3^6 [#permalink] New post   24 Oct 2022, 08:31
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Quantity A
Quantity B
The average (arithmetic mean) of \(3^2,3^4,3^6\)
\(3^4\)




A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.


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A
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Re: The average (arithmetic mean) of 3^2,3^4,3^6 [#permalink] New post   25 Oct 2022, 00:42
1
============================================================

Theory
    ‣‣‣ Average or Arithmetic Mean = (Sum Of All The Numbers) / (Total Number Of Numbers)

============================================================

Quantity A: The average (arithmetic mean) of \(3^2,3^4,3^6\)

=> Average = \(\frac{3^2 + 3^4 + 3^6}{3}\) = \(3 + 3^3 + 3^5\) > \(3^4\)

Clearly, Quantity A > Quantity B

So, Answer will be A.
Hope it helps!

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Re: The average (arithmetic mean) of 3^2,3^4,3^6 [#permalink]
25 Oct 2022, 00:42
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