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Re: If x > 0 and 4x/(x^2 −3x) − 2/7 = 0 what is the value of x? [#permalink]
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Bunuel wrote:
If x > 0 and 4x(x23x)27=0 what is the value of x?

Show: :: OA
17



Given: 4x(x23x)27=0

Add 27 to both sides to get: 4x(x23x)=27

Cross multiply to get: (7)(4x)=(2)(x23x)

Expand both sides: 28x=2x26x

Subtract 28x from both sides: 0=2x234x

Divide both sides by 2: 0=x217x

Factor: 0=x(x17)

So, EITHER x = 0 OR x = 17

Since we're told that x > 0, we can conclude that x = 17

Answer: 17
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If x>0 and 4x/x^2-3x-2/7=0, what is the value of x? [#permalink]
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If x>0 and 4xx23x27=0, what is the value of x?


Show: ::
17


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Re: If x>0 and 4x/x^2-3x-2/7=0, what is the value of x? [#permalink]
2
Given that x>0 and 4xx23x27=0 and we need to find the value of x

4xx23x27=0
=> 4xx23x=27

Cross multiplying by 7 and x23x we get

7 *4x = 2 * (x23x)

Dividing both sides by 2 we get
7*2x = x23x
=> x23x - 14x = 0
=> x217x = 0
=> x*(x-17) = 0
=> x = 0 or x = 17

Given that x > 0
=> x = 17

So, Answer will be 17
Hope it helps!
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Re: If x > 0 and 4x/(x^2 3x) 2/7 = 0 what is the value of x? [#permalink]
1
this is how I solved it... multiply both sides by 7*(x^2 - 3x) to get 7(4x) - 2 (x^2 - 3x) = 0
which gives us 28x - 2x^2 + 6x = 0. which is also 34x - 2x^2 = 0.
then we add 2x^2 to both sides to get 34x = 2x^2. divide both sides by 2 to get 17x = x^2. since x > 0, we divide x by both sides to get x = 17. Does this work Brent?
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Re: If x > 0 and 4x/(x^2 3x) 2/7 = 0 what is the value of x? [#permalink]
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