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Joan is allowed to invite 3 of her friends to join her on a family cam
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26 Oct 2022, 01:20
26 Oct 2022, 01:20
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Question Stats:
87% (00:38) correct
12% (00:35) wrong based on 8 sessions
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Joan is allowed to invite 3 of her friends to join her on a family camping trip. If Joan has 10 friends, in how many ways can she invite 3 of them?
(A) 27
(B) 120
(C) 240
(D) 360
(E) 720
(A) 27
(B) 120
(C) 240
(D) 360
(E) 720
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GRE Math Essentials (2022)
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GRE - Math Book
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Joined: 02 Jan 2020
Status:GRE Quant Tutor
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Location: India
Concentration: General Management
Schools: XLRI Jamshedpur, India - Class of 2014
GMAT 1: 700 Q51 V31
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WE:Engineering (Computer Software)
Re: Joan is allowed to invite 3 of her friends to join her on a family cam
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26 Oct 2022, 08:57
26 Oct 2022, 08:57
1
Given that Joan is allowed to invite 3 of her friends to join her on a family camping trip. And we need to find If Joan has 10 friends, in how many ways can she invite 3 of them
We need to select 3 people out of 10. Since its a selection so order does not matter => Combination
=> 10C3 ways = \(\frac{10!}{3!*(10-3)!}\) = \(\frac{10*9*8*7!}{3!*7!}\) = 120
So, Answer will be B
Hope it helps!
We need to select 3 people out of 10. Since its a selection so order does not matter => Combination
=> 10C3 ways = \(\frac{10!}{3!*(10-3)!}\) = \(\frac{10*9*8*7!}{3!*7!}\) = 120
So, Answer will be B
Hope it helps!
gmatclubot
Re: Joan is allowed to invite 3 of her friends to join her on a family cam [#permalink]
26 Oct 2022, 08:57
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