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a>0 and b>0

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Carcass
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a>0 and b>0 [#permalink] New post   Updated on: 02 Nov 2022, 00:32
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a>0 and b>0

Quantity A
Quantity B
\( [a+b]\)
\(\sqrt{[a+b]^2}\)



A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.


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C

Originally posted by Carcass on 01 Oct 2022, 22:23.
Last edited by Carcass on 02 Nov 2022, 00:32, edited 1 time in total.
Fixed OA
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Carcass
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Re: a>0 and b>0 [#permalink] New post   31 Oct 2022, 10:21
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The two quantities in the end will be positive

However, both a and b could be the same number and the two Qs are equal and the answer C


C is the definitive answer
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Re: a>0 and b>0 [#permalink] New post   01 Nov 2022, 15:09
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Carcass wrote:
The two quantities in the end will be positive

However, both a and b could be the same number and the two Qs are equal and the answer C

Or a and b can be different or fractions and the answer would depend

D is the definitive answer



don't both of them equate to [a+b] because ([a+b)]^2)^1/2 is just [a+b]
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Re: a>0 and b>0 [#permalink] New post   01 Nov 2022, 21:25
1
Carcass wrote:
The two quantities in the end will be positive

However, both a and b could be the same number and the two Qs are equal and the answer C

Or a and b can be different or fractions and the answer would depend

D is the definitive answer


I tried a = 10 b = 1 answer is C
and a= 1/2 and b= 1/4 answer is C

I think the case u are talking about is where the a & b could be + or -ve.
May you pls elaborate ?
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Re: a>0 and b>0 [#permalink] New post   02 Nov 2022, 00:31
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You are right folks. My bad

QB after simplified is just a+b

C is the answer but still the book report D

Mah ...........

Thank you both
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Re: a>0 and b>0 [#permalink] New post   04 Nov 2022, 21:59
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I think the answer could be D because the root could be positive or negative, so it could be
(a + b) : in which case theyre equal
or
-(a + b) : in which case A is greater

hence D?
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Re: a>0 and b>0 [#permalink] New post   11 Nov 2023, 21:41
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: a>0 and b>0 [#permalink]
11 Nov 2023, 21:41
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