\(\frac{A}{P} = \frac{2}{3}\) and \(\frac{C}{P} = \frac{2}{1}\)

Lets make P equal in both the fractions:
\(\frac{A}{P} = \frac{2}{3}\) and \(\frac{C}{P} = \frac{(2)(3)}{(1)(3)}\)

Hence, the ratio of \(A : P : C = 2 : 3 : 6\)

Now, \(P = \frac{P}{(A + P + C)}(Total) = \frac{3}{(2 + 3 + 6)}(33) = \frac{3}{11}(33) = (3)(3) = 9\)

Col. A: 9
Col. B: 8

Col. A > Col. B
Hence, option A