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Re: In the square above, 12w = 3x = 4y. What fractional part of the square
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14 Nov 2022, 07:52
12w = 3x = 4y
x = 4w &
y = 3w
Area of square \(= (5w)^2 = 25w^2\) .............. (1)
Area of unshaded region (4 right triangles) \(= \frac{1}{2} w * 4w + \frac{1}{2} 2 w^2 + \frac{1}{2} 4w * 3w + \frac{1}{2} w * 4w\)
\(= 2w^2 + w^2 + 6w^2 + 2w^2 = 11w^2\) ............. (2)
Area of shaded region \(= 25w^2 - 11w^2 = 14w^2\)
Fraction \(= \frac{14}{25}\)
Answer: B