GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
What is the least possible distance between a point on the circle x^2
[#permalink]
10 Nov 2022, 10:32
10 Nov 2022, 10:32
Expert Reply
00:00
Question Stats:
100% (03:06) correct
0% (00:00) wrong based on 3 sessions
Hide Show timer Statistics
What is the least possible distance between a point on the circle \(x^2 + y^2 = 1\) and a point on the line \(y = \frac{3}{4}*x - 3\)?
A) 1.4
B) \(\sqrt{2}\)
C) 1.7
D) \(\sqrt{3}\)
E) 2.0
A) 1.4
B) \(\sqrt{2}\)
C) 1.7
D) \(\sqrt{3}\)
E) 2.0
Part of the project: GRE QCQ & PS 3 Questions Every One DAILY Challenge - (2022) - Gain 20 Kudos & Get FREE Access to GRE Prep Club TESTS
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
Re: What is the least possible distance between a point on the circle x^2
[#permalink]
14 Nov 2022, 07:55
14 Nov 2022, 07:55
1
Expert Reply
Use the formula
D = |Am+Bn+C|/ SQRT(A^2 + B^2) where Ax+By+C = 0
put (m, n) =0, 0 = center of circle
we get D = 12/5 thus required distance is D-1 = 12/5 -1 = 7/5 = 1.4
Answer: A
D = |Am+Bn+C|/ SQRT(A^2 + B^2) where Ax+By+C = 0
put (m, n) =0, 0 = center of circle
we get D = 12/5 thus required distance is D-1 = 12/5 -1 = 7/5 = 1.4
Answer: A
gmatclubot
Re: What is the least possible distance between a point on the circle x^2 [#permalink]
14 Nov 2022, 07:55
Moderators:
