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A jogger leaves home at 9:00 a.m., and, without stopping, runs 3 miles
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15 Aug 2021, 12:58
15 Aug 2021, 12:58
Expert Reply
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Question Stats:
66% (01:57) correct
33% (02:02) wrong based on 9 sessions
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A jogger leaves home at 9:00 a.m., and, without stopping, runs 3 miles to the local running track, runs around the track 8 times, and then runs home along the same route for a total distance of 8 miles. If the jogger arrives home at 10:20 a.m., what is the jogger’s average jogging speed?
Show: :: OA
6 miles
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A jogger leaves home at 9:00 a.m., and, without stopping, runs 3 miles
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15 Aug 2021, 21:55
15 Aug 2021, 21:55
1
Carcass wrote:
A jogger leaves home at 9:00 a.m., and, without stopping, runs 3 miles to the local running track, runs around the track 8 times, and then runs home along the same route for a total distance of 8 miles. If the jogger arrives home at 10:20 a.m., what is the jogger’s average jogging speed?
Show: :: OA
6 miles
Total distance = 8 miles
total Time = 80 minutes = \(\frac{80}{60}\) = 1.33 hrs
Average speed \(= \frac{total distance}{total time} = \frac{8}{1.33} = 6\)
Re: A jogger leaves home at 9:00 a.m., and, without stopping, runs 3 miles
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17 Nov 2022, 13:36
17 Nov 2022, 13:36
Is there a way to know in what specific ratio we should report the answer? Might as well express it in miles/minute
