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Willard can paint a room in 6 hours working alone. Jada can do the sam

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Willard can paint a room in 6 hours working alone. Jada can do the sam [#permalink] New post   09 Jul 2021, 07:39
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Willard can paint a room in 6 hours working alone. Jada can do the same job in 4 hours working alone.

Quantity A
Quantity B
The number of hours it should take Willard and Jada to paint the room working together
\(2 \frac{1}{2}\) hours



A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
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B
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Willard can paint a room in 6 hours working alone. Jada can do the sam [#permalink] New post   09 Jul 2021, 08:03
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Formula :

When a person can do a job in \(x\) hours and another do the same job in \(y\) hours,
then the time needed when both work together to complete the job = \(\frac{xy}{x+y}\)

Qt A

Time = \(\frac{6*4}{6+4}\) = \(2\frac{2}{5}\)

Qt B > Qt A

Answer B
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Re: Willard can paint a room in 6 hours working alone. Jada can do the sam [#permalink] New post   19 Nov 2022, 06:30
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: Willard can paint a room in 6 hours working alone. Jada can do the sam [#permalink]
19 Nov 2022, 06:30
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